SOLUTION: Find three consecutive integers such that the sum of the first integer and twice the second integer is 542 more than the third integer.

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Find three consecutive integers such that the sum of the first integer and twice the second integer is 542 more than the third integer.      Log On


   



Question 261265: Find three consecutive integers such that the sum of the first integer and twice the second integer is 542 more than the third integer.
Answer by Stitch(470) About Me  (Show Source):
You can put this solution on YOUR website!
The equation: +X+%2B+2%2A%28X%2B1%29+=+%28X+%2B+2%29+%2B+542
Simplify the equation
X+%2B+2X+%2B+2+=+X+%2B+544
Subtract 2 from both sides
X+%2B+2X+=+X+%2B+542
Subtract X from both sides
2X+=+542
Divide both sides by 2
highlight%28X+=+271%29
So the numbers are; 271, 272 & 273

Check the answer
-----------------
271+%2B+2%2A272+=+273+%2B+542 Simplify
highlight%28815+=+815%29