Question 261047: Please help me.... I can't remember the basics for this problem:
A rectangle's length is 6 meters more than twice its width. The perimeter is 60 meters. Find the length in meters.
We aren't supposed to SOLVE the equation, just write each system of equation.
I got: 6+2(w)=60
is that correct?
Answer by Greenfinch(383)   (Show Source):
You can put this solution on YOUR website! Call the width W, then the length is 2W + 6
The perimeter is therefore 2(W + 2W + 6)
or 6W + 12
as it is = 60, then 6W is 48, W = 8 and length is 22 metres
OR
1/2 perimeter is 30
so width + length is 30
so 3W + 6 = 30
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