SOLUTION: A woman invested a total of $9000 in two accounts, one earning 6.5% annual interest and the other earning 8% annual interest. After 1 year, her combined interest was $678.87. How m

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: A woman invested a total of $9000 in two accounts, one earning 6.5% annual interest and the other earning 8% annual interest. After 1 year, her combined interest was $678.87. How m      Log On


   

Question 260957: A woman invested a total of $9000 in two accounts, one earning 6.5% annual interest and the other earning 8% annual interest. After 1 year, her combined interest was $678.87. How much did she invest in the account paying 8% interest?
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
.08x+.065(9,000-x)=678.87
.08x+585-.065x=678.87
15x=678.87-585
.015x=93.87
x=903.87/.015
x=$6,258 amount invested @ 8%.
Proof:
.08*6,258+.065(9,000-6,258)=678.87
500.64+.065*2,742=678.87
500.64+178.23=678.87
678.87=678.87