Question 260813: You need to choose between two telephone plans for local calls. Plan A charges $25 per month for unlimited calls. Plan B has a monthly fee of $13 with a charge of $0.06 per local call. How many local telephone calls in a month make Plan A the better deal?
I know that I am supposed to use the greater than and less than signs. Please help!!
Thank You!!!!
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! Plan A charges $25 per month for unlimited calls.
Plan B charges $13 per month plus $.06 per call.
You want to know when plan A costs less than plan B.
set up an equation as follows:
Cost for Plan A = $25.00
Cost for Plan B = $13.00 + .06 * x
x = number of calls per month.
you want to know when plan A Costs are smaller than plan B costs.
your equation is:
Plan A Costs < Plan B costs.
this becomes:
25 < 13 + .06 * x
subtract 13 from both sides of this equation to get:
25 - 13 < .06 * x
simplify to get:
12 < .06 * x
divide both sides of this equation by .06 to get:
12/.06 < x
simplify to get:
200 < x
this is the same as:
x > 200
Plan A at $25.00 per month will be cheaper when the number of minutes used per month is > 200.
200 should be the break even point.
200 * .06 + 13 = 12 + 13 = 25.
when the minutes go above 200, plan A at $25 per month will be cheaper.
at 201 minutes, plan B costs .06 * 201 = $12.06 + $13.00 = $25.06 which is more expensive than plan A.
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