SOLUTION: A truck can be rented from Basic Rental for $50 per day plus $0.20 per mile. Roadrunners charges $20 per day plus $0.50 per mile to rent the same truck. How many miles must be driv

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: A truck can be rented from Basic Rental for $50 per day plus $0.20 per mile. Roadrunners charges $20 per day plus $0.50 per mile to rent the same truck. How many miles must be driv      Log On


   

Question 260811: A truck can be rented from Basic Rental for $50 per day plus $0.20 per mile. Roadrunners charges $20 per day plus $0.50 per mile to rent the same truck. How many miles must be driven in a day to make the rental cost for Basic Rental a better deal than that for Roadrunners?
All I know is that I am supposed to used the greater than and less than signs.
Thank You!!!!!
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
50+.20X<20+.50X
.20X-.50X<20-50
-.30X<-30
X>-30/-.30 NOTE: THE SIGN CHANGES WHEN DIVIDING BY A NEGATIVE VALUE.
X>100 GREATER THAN 100 MILES DRIVEN MAKES THE BASIC RENTAL OFFER A BETTER DEAL.
PROOF:
50+.20*100<20+.50*100
50+20<20+50
70<70