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put this solution on YOUR website! (2-4i)/(1+3i)
3 - 4i
——————
1 + 3i
The denominator is 1 + 3i.
I. Form its conjugate by:
a. Keeping the first term as it is:
1
b. Changing the sign of the second term
change +3i to -3i
c. Putting these together
1 - 3i
d. Forming a fraction which equals one by placing this
conjugate over itself.
1 - 3i
——————
1 - 3i
2. Multiply original fraction by this fraction:
3 - 4i 1 - 3i
—————— × ——————
1 + 3i 1 - 3i
3. Put parentheses around all numerators and denominators
(3 - 4i) (1 - 3i)
———————— × ————————
(1 + 3i) (1 - 3i)
4. Write as one fraction:
(3 - 4i)(1 - 3i)
————————————————
(1 + 3i)(1 - 3i)
5. Use FOIL to multiply out numerator and denominator
3 - 9i - 4i + 12i²
————————————————————
1 - 3i + 3i - 9i²
6. Combine terms in numerator and denominator
3 - 13i + 12i²
———————————————
1 - 9i²
7. Replace i² by its equivalent -1
3 - 13i + 12(-1)
——————————————————
1 - 9(-1)
8. Simplify
3 - 13i - 12
——————————————————
1 + 9
-9 - 13i
——————————
10
9. Write as two fractions
-9 13i
———— - —————
10 10
10. Write i as multiplied by the fraction 13/10
-9 13
———— - ———— i
10 10
Edwin
AnlytcPhil@aol.com