SOLUTION: Hi :o)
Last calculus question if anyone can help???
Find derivative of y = (x-1)³(x²-2)²
I thought I'd need to use both the product and chain rules, so tried;
u=(x-1)³ d
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Rational-functions
-> SOLUTION: Hi :o)
Last calculus question if anyone can help???
Find derivative of y = (x-1)³(x²-2)²
I thought I'd need to use both the product and chain rules, so tried;
u=(x-1)³ d
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Question 260676: Hi :o)
Last calculus question if anyone can help???
Find derivative of y = (x-1)³(x²-2)²
I thought I'd need to use both the product and chain rules, so tried;
u=(x-1)³ du^n/dx=3(x-1)²(1)
v=(x²-2)² dv^n/dx=2(x²-2)^1(2x)
= {(x-1)³[3(x-1)²(1)]} + {(x²-2)²[2(x²-2)^1(2x)]}
= [(x-1)³3(x-1)²] + [(x²-2)²4x(x²-2)]
= 3(x-1)^5 + 4x(x²-2)^3
...does that look right? Can I go further?
Thanks so, so much again :o) Answer by jim_thompson5910(35256) (Show Source):
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