SOLUTION: One car left a city at 2:00 PM and traveled at an average speed of 40 miles per hour. A second car left at 4:00 PM, traveled the same route and overtook the first car at 9:00 PM.
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Question 260658: One car left a city at 2:00 PM and traveled at an average speed of 40 miles per hour. A second car left at 4:00 PM, traveled the same route and overtook the first car at 9:00 PM. What was the average speed in miles per hour of the second car? Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! D=RT
D=40*7 FOR THE FIRST CAR.
D=R5 FOR THE SECOND CAR.
40*7=5R
5R=280
R=280/5
R=56 MPH. IS THE SPEED OF THE SECOND CAR.
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