Question 260522: On August 28, the Corwin family recieved 27 pieces of mail, consisting of magazines, bills, letters and ads. If they recieved the same number of magazines as letters, three more bills than letters, and five more ads than bills, how many magazines did they recieve? Write an algebraic equation. Solve your equation.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! On August 28, the Corwin family recieved 27 pieces of mail, consisting of magazines, bills, letters and ads.
m + b + L + a= 27
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If they recieved the same number of magazines as letters, three more bills than letters, and five more ads than bills, how many magazines did they recieve? Write an algebraic equation.
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m = L
b = L + 3
a = b + 5
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Substitute to get:
L + (L+3) + L + (L+3)+5 = 27
4L + 11 = 27
4L = 16
L = 4 = m (# of letters and number of magazines)
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b = L+3 ; b = 7 (# of bills)
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a = b + 5 = 12 (# of ads)
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Cheers,
Stan H.
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