You can put this solution on YOUR website! a)
cos 120 = -1/2
cos 330 = sqrt(3)/2
sin 90 = 1
cos 315 = sqrt(2)/2
so, we get
which is
and finally
--
b) (sin^2 210)/ (3cos^2 120+cos150)
sin 210 = -1/2
sin^2(210) = 1/4
cos 120 = -1/2
cos^2(120) = 1/2
3cos^2(120) = 3/2
cos150 = -sqrt(3)/2
so, we get
which becomes
rationalizing, we get