SOLUTION: Michael drove to a friend's house at a rate of 40mph. He returned by the same route at a rate of 45mph. The driving time for the round trip was 4 hours. What is the distance Michae

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Michael drove to a friend's house at a rate of 40mph. He returned by the same route at a rate of 45mph. The driving time for the round trip was 4 hours. What is the distance Michae      Log On

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Question 260260: Michael drove to a friend's house at a rate of 40mph. He returned by the same route at a rate of 45mph. The driving time for the round trip was 4 hours. What is the distance Michael traveled?
Found 2 solutions by checkley77, richwmiller:
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
D=RT
D=45T
D=40(4-T)
BECAUSE THE DISTANCES ARE THE SAME WE HAVE:
45T=40(4-T)
45T=160-40T
45T+40T=160
85T=160
T=160/85
T=1.882 HOURS FOR THE 45 MPH TRIP.
4-1.882=2.118 HOURS FOR THE 40 MPH TRIP.
D=45*1.882=84.7 MILES IS THE ONE WAY DISTANCE.
D=40*2.118=84.7 DITTO.
TOTAL DISTANCE TRAVELEDIS:
2*84.7=169.4 MILES.

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
40*t=45(4-t)
40t=180-45t
85t=180
17t=36
t=36/17 =2 2/17
40*36/17
4-2 2 /17
32/17*45=40*36/17
total trip
84 12/17 each way
169 7/17 round trip