Question 260062: Suppose that the New England Colonials baseball team is equally likely to win a game as not to win it. If 4 Colonials games are chosen at random, what is the probability that exactly 3 of those games are won by the Colonials?
Round your response to at least three decimal places.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Suppose that the New England Colonials baseball team is equally likely to win a game as not to win it. If 4 Colonials games are chosen at random, what is the probability that exactly 3 of those games are won by the Colonials?
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P(win) = P(lose) = 1/2
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It is abinomial problem with n = 4, p = 1/2 ; x = 3
Ans: binompdf(4, 1/2, 3) = 4C3(1/2)^3(1/2) = 4*(1/2)^4 = 4*(1/16) = 1/4
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Cheers,
Stan H.
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