|
Question 2600: Would you please be able to give me a detailed description on how to do this linear quetion?
QUESTION: A rock climber climbs a cliff at a steady rate. She starts at the bottom of the cliff, which is 1200m above sea level. 8minutes into the climb she is 1224m above sea level.
a. Let y=metres above the sea
and x=Climbing time in minutes.
Write the coordinates of the y-intercept.
b. What are the coordinates of another point?
C.How many metres is she climbing per a minute?
D.What is teh equation the describes her height above sea level while she is climbing?
E. She finishes climbing the cliff in 18 minutes. How high is she above sea level?
Thank you so so much if u can help i need detailed exlanations if possible thanks
Answer by longjonsilver(2297)   (Show Source):
You can put this solution on YOUR website! at time x=0, the height of the climber, y = 1200. This is your answer to part a) since the y-intercept is where x=0.
b. other coordinates are (8, 1224)
c. in 8 minutes, she climbs 24 metres. So, in 1 minute, she climbs? 3 metres. So she climbe 3 metres ever min... that is her rate.
Now "rate" is another word for gradient...so, knowing your y=mx+c standard form of a straight line, gives:
d. y = 3x+1200
e. in 18 minutes...
y = 3(18) + 1200
y = 54 + 1200
y = 1254m
make sense?
jon
|
|
|
| |
