SOLUTION: Solve using quadratic formula. My book says the answer is {{{1+- sqrt (29)/(4)}}} 4x^2-2x-7=0 x={{{(-2+- sqrt(-2^2-4*4*-7))/(2*4)}}} x={{{2+-sqrt(4+112)/(8)}}} x={{{2+-sqrt(116

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Solve using quadratic formula. My book says the answer is {{{1+- sqrt (29)/(4)}}} 4x^2-2x-7=0 x={{{(-2+- sqrt(-2^2-4*4*-7))/(2*4)}}} x={{{2+-sqrt(4+112)/(8)}}} x={{{2+-sqrt(116      Log On


   

Question 259971: Solve using quadratic formula. My book says the answer is 1%2B-+sqrt+%2829%29%2F%284%29
4x^2-2x-7=0
x=%28-2%2B-+sqrt%28-2%5E2-4%2A4%2A-7%29%29%2F%282%2A4%29
x=2%2B-sqrt%284%2B112%29%2F%288%29
x=2%2B-sqrt%28116%29%2F%288%29
I need help at this point. Thank you
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Solve using quadratic formula. My book says the answer is 1%2B-+sqrt+%2829%29%2F%284%29
4x^2-2x-7=0
x=%28-2%2B-+sqrt%28-2%5E2-4%2A4%2A-7%29%29%2F%282%2A4%29
x=2%2B-sqrt%284%2B112%29%2F%288%29
x=2%2B-sqrt%28116%29%2F%288%29
Note that we can factor to reveal a perfect square inside the radical
x=2%2B-sqrt%284%2A29%29%2F%288%29
extract the perfect square
x=%282%2B-2%2Asqrt%2829%29%29%2F%288%29
You can cancel both 2's into the 8
x=1%2B-sqrt%2829%29%2F%284%29