Question 259968: If r = s^2t^2, r is not equal to zero, and the values of s and t are doubled, then how many times is the value of r increased? Answer by rfadrogane(214) (Show Source):
You can put this solution on YOUR website! If s and t are double, then
the new value of r is..
r = (2s)^2(2t)^2 = 16s^2t^2
thus, the new value of r is increased by 16 times----ans