SOLUTION: If 4x + 4y = 20 and 8x^-1/2 = 4^-1, then what is the value of y?

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Question 259963: If 4x + 4y = 20 and 8x^-1/2 = 4^-1, then what is the value of y?
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
8x^-1/2 = 4^-1
8/sqrt(x)=1/4
sqrt(x)=32 multiply each side by 4sqrt(x)
x=32^2
=1024
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Ed