Question 259927: Hello Again,
I had already sent this question and got part of the answer but I had forgot to send the second part, and I think that I figured out the second part but not for sure I may be wrong.
Question:
2.Use the method specified to perform the hypothesis test for the population
mean . A local brewery distributes beer in bottles labeled 32 ounces. A government agency thinks that the brewery is cheating its customers. The agency select 50 of these bottles, measures their contents, and obtains a sample mean of 31.6 ounces with a population standard deviation of 0.70 ounce. At - this symbol means the level of significance alpha = 0.01, test the agency’s claim that the brewery is cheating its customers
b. Use the P-value method.
1. H0 : u=32
Ha :
2. = u is greater than 32
3. Test statistics: 31.6-32/0.7/square root 50=4.0406
4. P-value or critical z0 or t0. df (-100 -4.0406.49) =0.0009379
5. Rejection Region:
6. Decision:
7. Interpretation:
I am going based on from what I had gotten help on the first part of the question, and also I based it on the formula used in the book.
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 2.Use the method specified to perform the hypothesis test for the population
mean . A local brewery distributes beer in bottles labeled 32 ounces. A government agency thinks that the brewery is cheating its customers. The agency select 50 of these bottles, measures their contents, and obtains a sample mean of 31.6 ounces with a population standard deviation of 0.70 ounce. At - this symbol means the level of significance alpha = 0.01, test the agency’s claim that the brewery is cheating its customers
b. Use the P-value method.
1.
Ho : u=32
Ha : u < 32 (because the problem claims there is cheating which is less than 32)
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2. = 1%
3. Test statistics:
t(31.6) = (31.6-32)/[0.7/square root(50) = -4.0406
4. P-value or critical z0 or t0. df (-100 -4.0406.49) = 0.00009379
Note: I changed your p-value: It should be 9.378x10^-5 = 0.00009379
5. Rejection Region:
For a left tail test with alpha = 1% and df=49 the
rejection Region is t< invT(0.01,49) = -2.4049
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6. Decision: Since p < 1%, reject Ho.
7. Interpretation:
The test results support rejecting the manufacturer's claim
and provides strong evidence that the brewery is cheating.
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Cheers,
Stan H.
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