SOLUTION: Can you help me factor the polynomial 3a^2+a-14

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Question 259024: Can you help me factor the polynomial 3a^2+a-14
Found 2 solutions by richwmiller, drk:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
(a-2)*(3a+7)
Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)


Looking at the expression 3a%5E2%2Ba-14, we can see that the first coefficient is 3, the second coefficient is 1, and the last term is -14.



Now multiply the first coefficient 3 by the last term -14 to get %283%29%28-14%29=-42.



Now the question is: what two whole numbers multiply to -42 (the previous product) and add to the second coefficient 1?



To find these two numbers, we need to list all of the factors of -42 (the previous product).



Factors of -42:

1,2,3,6,7,14,21,42

-1,-2,-3,-6,-7,-14,-21,-42



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to -42.

1*(-42) = -42
2*(-21) = -42
3*(-14) = -42
6*(-7) = -42
(-1)*(42) = -42
(-2)*(21) = -42
(-3)*(14) = -42
(-6)*(7) = -42


Now let's add up each pair of factors to see if one pair adds to the middle coefficient 1:



First NumberSecond NumberSum
1-421+(-42)=-41
2-212+(-21)=-19
3-143+(-14)=-11
6-76+(-7)=-1
-142-1+42=41
-221-2+21=19
-314-3+14=11
-67-6+7=1




From the table, we can see that the two numbers -6 and 7 add to 1 (the middle coefficient).



So the two numbers -6 and 7 both multiply to -42 and add to 1



Now replace the middle term 1a with -6a%2B7a. Remember, -6 and 7 add to 1. So this shows us that -6a%2B7a=1a.



3a%5E2%2Bhighlight%28-6a%2B7a%29-14 Replace the second term 1a with -6a%2B7a.



%283a%5E2-6a%29%2B%287a-14%29 Group the terms into two pairs.



3a%28a-2%29%2B%287a-14%29 Factor out the GCF 3a from the first group.



3a%28a-2%29%2B7%28a-2%29 Factor out 7 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.



%283a%2B7%29%28a-2%29 Combine like terms. Or factor out the common term a-2



===============================================================



Answer:



So 3%2Aa%5E2%2Ba-14 factors to %283a%2B7%29%28a-2%29.



In other words, 3%2Aa%5E2%2Ba-14=%283a%2B7%29%28a-2%29.



Note: you can check the answer by expanding %283a%2B7%29%28a-2%29 to get 3%2Aa%5E2%2Ba-14 or by graphing the original expression and the answer (the two graphs should be identical).


Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
Here is the original problem
3a%5E2%2Ba-14
there are several ways to factor. The basic idea is to get (ax+b)(cx+d)
--
step 1 - multiply 3 and 14 to get 42.
we want 2 factors of 42 that add to 1, but are different signs.
we get 7 + (-6)
--
step 2 - replace 1a with 7a - 6a like this
3a%5E2+-+6a+%2B+7a+-+14
step 3 - group the first pair and last pair and find the GCF of each like this
%283a%5E2+-+6a%29+%2B+%287a+-+42%29
finding GCF's we get
3a%28a+-+2%29+%2B+7%28a+-+2%29
notice the parenthesis are the same; this is what we want to happen.
step 4 - find another GCF as
%28a-2%29%283a%2B7%29
and you have factored.