Question 25896: Find the lengths of the medians of the triangle with verticies A(1,0), B(3,6) AND C(8,2). (A median is a line segment from a vertex to the midpoint of the opposite side)
Answer by venugopalramana(3286)   (Show Source):
You can put this solution on YOUR website! Find the lengths of the medians of the triangle with verticies A(1,0), B(3,6) AND C(8,2). (A median is a line segment from a vertex to the midpoint of the opposite side)
LET THE MID POINTS OF BC,CA AND AB.... BE .......D,E,AND F.
MID POINT OF (X1,Y1) AND (X2,Y2)IS GIVEN BY (X1+X2)/2 AND (Y1+Y2)/2
HENCE
D=(3+8)/2 AND (6+2)/2..THAT IS...(5.5 ,4)
SIMILARLY
E = (4.5,1)
AND
F = (2,3)
NOW DISTANCE BETWEEN TWO POINTS (X1,Y1) AND (X2,Y2) IS GIVEN BY
SQRT.{(X1-X2)^2+(Y1-Y2)^2}...HENCE MEDIAN
AD = SQRT.{(5.5 - 1)^2+(4-0)^2}=SQRT(36.25)
YOU CAN FIND THE OTHER MEDIANS BE AND CF IN THE SAME WAY
|
|
|
