SOLUTION: Here’s the problem: For a car renting for $15 per day plus $.10 per mile, the cost for 1 day is C(m)=15+o.10m (dollars) where m is the number of miles driven. If the person p

Algebra ->  Functions -> SOLUTION: Here’s the problem: For a car renting for $15 per day plus $.10 per mile, the cost for 1 day is C(m)=15+o.10m (dollars) where m is the number of miles driven. If the person p      Log On


   



Question 258929: Here’s the problem:
For a car renting for $15 per day plus $.10 per mile, the cost for 1 day is
C(m)=15+o.10m (dollars)
where m is the number of miles driven. If the person paid $35.30 for 1 day’s rental, how far did the person drive?
Now I can look at this and know what the answer is, but I have to solve it using
L(a)=-2/3+150
I not only do not understand how to do it – I don’t understand the function.
Could you guide me through this please?

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
For a car renting for $15 per day plus $.10 per mile, the cost for 1 day is
C(m)=15+0.10m (dollars) where m is the number of miles driven.
If the person paid $35.30 for 1 day’s rental, how far did the person drive?
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Solve 15 + 0.10m = 35 for "m"
Subtract 15 from both sides to get:
0.10m = 20
m = 20/(0.10)
m = 20/(1/10)
m = 20 miles
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Cheers,
Stan H.