Question 258804: find 3 consecutive integers such that the square root of the first plus the product of the other two is 46. Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! The first integer has to be a square so that the square root is an integer. , , , , , , , , ,
We're already over 46 and this function will only increase.
No solution.