SOLUTION: A photographer is mixing 2 liters of a 10% acetic acid solution with a 5% solution to get a 7% solution. How many liters of the 5% solution should he add?
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Question 258552: A photographer is mixing 2 liters of a 10% acetic acid solution with a 5% solution to get a 7% solution. How many liters of the 5% solution should he add? Found 2 solutions by drk, palanisamy:Answer by drk(1908) (Show Source):
You can put this solution on YOUR website! This is a mixture problem. Here is the table based on the given information:
ACID . . . . . . . .% . . . . . . . . .LITER . . . . . . . . . % x Liter
10% . . . . . . . . .10 . . . . . . . .. 2 . . . . . . . . . . . .20
5% . . . . . .. . . . .5 . . . . . . . . .x . . . . . . . .. . . . . 5x
MIX . . . . . . . . . .7 . . . . . . . . x+2 . . . . . .. . . . . .7x + 14
we don't know the 5%, so call it x. The total liters is the sum of these two, or x + 2.
Now we have the last column as
20 + 5x = 7x + 14
solving for x, we get
6 = 2x
3 = x
We need 3 liters of the 5% solution.
You can put this solution on YOUR website! A photographer is mixing 2 liters of a 10% acetic acid solution with a 5% solution to get a 7% solution.
Let x liters of the 5% solution he add.
Then, 2*(10/100)+x*(5/100) = (2+x)*(7/100)
20+5x = 14+7x
20-14 = 7x-5x
6 = 2x
2x = 6
x = 3
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