SOLUTION: Solve the equation using the quadratric formula....find the solution set. 2x^2-3x-1=0

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Question 258510: Solve the equation using the quadratric formula....find the solution set.
2x^2-3x-1=0
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
2x^2-3x-1=0
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x=(3+-sqrt[-3^2-4*2*-1])/2*2
x=(3+-sqrt9+8)/4
x=(3+-sqrt17)/4
x=(3+-4.123)/4
x=(3+4.7123)/4
x=7.7123/4
x=1.78 ans.
x=(3-4.123)/4
x=-1.123/4
x=-.28 ans.