SOLUTION: how would you solve (9x-3) (x^2+2x+1) in the horizontal method?

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Question 258484: how would you solve (9x-3) (x^2+2x+1) in the horizontal method?
Found 2 solutions by stanbon, drk:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
how would you solve
(x^2+2x+1) in the horizontal method?
(9x-3)
--------------------
27x^3 + 18x^2 + 9x
........-3x^2.-.6x.-3
=============================
= 27x^3 + 15x^2 + 3x - 3
=======================================
Cheers,
Stan H.

Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
Here is the question:
(i) %289x-3%29+%28x%5E2%2B2x%2B1%29+
step 1 use distributive property by sending the 9x through all parts of the second parenthesis and get
(ii) 9x(x^2) + 9x(2x) + 9x(1)
this becomes
(iii) 9x^3 + 18x^2 + 9x
step 2 - send the -3 through using distributive property and get
(iv) (-3)(x^2) + (-3)(2x) + (-3)(1)
this becomes
(v) -3x^2 - 6x - 3
putting (iii) and (v) together, we get
(vi) 9x^3 + 18x^2 + 9x -3x^2 - 6x - 3
combine like terms to get
9x^3 +15x^2 + 3x - 3