SOLUTION: An airplane travels 900 miles from Houston to Miami in 6 hours against the wind. On its trip, with the wind, it takes only 5 hours. Find the rate of the airplane with no wind. Find

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: An airplane travels 900 miles from Houston to Miami in 6 hours against the wind. On its trip, with the wind, it takes only 5 hours. Find the rate of the airplane with no wind. Find      Log On


   

Question 258432: An airplane travels 900 miles from Houston to Miami in 6 hours against the wind. On its trip, with the wind, it takes only 5 hours. Find the rate of the airplane with no wind. Find the rate of the wind
Found 2 solutions by richwmiller, drk:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
rt=d
r*6=900=3*300=3*2*150=150
s*5=900=6*150=6*30*5=180
180-150=30
30/2=15 mph wind
airplane 165 mph with no wind.

Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
This is an RTD problem. WE can create a table based on the given information:
PLANE . . . . . .rate . . . . . . . .time . . . . . . . distance
against . . . . . .r-c . . . . . . . .6 . . . . . . . . . . .900
with . . . . . . .. r+c . . . . . . .. 5 . . . . . . .. . . . .900
RT=D
or r = D/T
r-c = 150
r+c = 180
adding down we get
2r = 330
r = 165
rate with no wind is 165 mph
c = 15 mph