SOLUTION: Hi guys, i really need your help. Could you please help me solve this problem:
An elevator went from the bottom to the top of a tower at an average speed of 4 m/s, remained at the
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An elevator went from the bottom to the top of a tower at an average speed of 4 m/s, remained at the
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Question 25824: Hi guys, i really need your help. Could you please help me solve this problem:
An elevator went from the bottom to the top of a tower at an average speed of 4 m/s, remained at the top for 90 s, and then returned to the bottom at 5 m/s. If the total elapsed time was 4 1/2 minutes, how high is the tower?
Thank you! Answer by Paul(988) (Show Source):
You can put this solution on YOUR website! 4 1/2 ----> 9/2 ---> 4.5
4.5 --> 270s
270s-90s=180s
Let the distance be x
So =180
The common multiple is 20
5x+4x=3600
9x=3600
x=400
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