SOLUTION: Two planes left at the same time from two airports which are 4500 miles apart and flew toward each other. In five hours they passed each other. The rate of the fast plane was tw
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Question 258228: Two planes left at the same time from two airports which are 4500 miles apart and flew toward each other. In five hours they passed each other. The rate of the fast plane was twice the rate of the slow plane. Find the rate of each plane.
Algebraic solutions only. Thank you! Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Two planes left at the same time from two airports which are 4500 miles apart and flew toward each other. In five hours they passed each other. The rate of the fast plane was twice the rate of the slow plane. Find the rate of each plane.
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Slow plane DATA:
rate = x mph ; time = 5 hrs. ; distance = rt = 5x miles
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Fast plane DATA:
rate = 2x mph ; time = 5 hrs. ; distance = rt = 10x miles
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Equation:
distance + distance = 4500 miles
5x + 10x = 4500
15x = 4500
x = 300 mph (slower plane rate)
2x = 600 mph (faster plane rate)
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Cheers,
Stan H.
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