SOLUTION: The perimeter of a rectangular garden is 40 ft. The width is 2 ft more than one half the length. Find the length and width.

Algebra ->  Rectangles -> SOLUTION: The perimeter of a rectangular garden is 40 ft. The width is 2 ft more than one half the length. Find the length and width.      Log On


   



Question 258165: The perimeter of a rectangular garden is 40 ft. The width is 2 ft more than one half the length. Find the length and width.
Found 2 solutions by stanbon, drk:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The perimeter of a rectangular garden is 40 ft. The width is 2 ft more than one half the length. Find the length and width.
-------------------
Perimeter = 2(L + W)
W = (1/2)L + 2
----
Substitute for "W" and solve for "L":
40 = 2(L + (1/2)L + 2)
20 = (3/2)L + 2
(3/2)L = 18
L = 12
===============
Cheers,
Stan H.

Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
The formula for perimeter is
(i) P = 2L + 2w
we also know that
(ii) w = (1/2)L + 2
by substitution, we get
(iii) 40+=+2L+%2B+2%28%281%2F2%29L+%2B+2%29
(iv) 40+=+2L+%2B+L+%2B+4
(v) 36+=+3L
L = 12
This means w = 8.