SOLUTION: I need to find an equation for the line that passes through (8,1/2) and (-1/3,6)and write the resulting equation in standard form

Algebra ->  Linear-equations -> SOLUTION: I need to find an equation for the line that passes through (8,1/2) and (-1/3,6)and write the resulting equation in standard form      Log On


   

Question 258089: I need to find an equation for the line that passes through (8,1/2) and (-1/3,6)and write the resulting equation in standard form
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
(8,1/2) and (-1/3,6)
Y=mX+b m=slope & b=the Y intercept.
m=(Y2-Y1)/(X2-X1)
m=(6-1/2)/(-1/3-8)
m=5.5/(-1/3-24/3)
m=5.5/-25/3
m=5.5*-3/25
m=-16.5/25=-3.3/5 ans.
1/2=-3.3*8/5+b
1/2=-26.4/5+b
b=1/2+26.4/5
b=2.5/5+26.4/5
b=28.9/5 the Y intercept.
Y=-3.3X/5+28.9/5 ans. for the line equation.
+graph%28+300%2C+200%2C+-6%2C+10%2C+-10%2C+10%2C+-3.3x%2F5+%2B28.9%2F5%29+ (graph 300x200 pixels, x from -6 to 10, y from -10 to 10, -3.3x/5 +28.9/5).