SOLUTION: The lengths of the sides of a triangle are 2, 5, and x cm; and the area is x square cm. compute the numerical value of x

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Question 258088: The lengths of the sides of a triangle are 2, 5, and x cm; and the area is x square cm. compute the numerical value of x
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!

Heron's formula for the area A of a triangle with
sides a,b, and c is

A=sqrt%28s%28s-a%29%28s-b%29%28s-c%29%29 where s=%28a%2Bb%2Bc%29%2F2

So we have a=2, b=5, and c=x and A = x.

We will eventually let a=2, b=5, c=x,
and A=x

But to make things easier we will first simplify
Heron's formula by first removing the square root and
secondly, eliminating s:

A=sqrt%28s%28s-a%29%28s-b%29%28s-c%29%29

A%5E2=s%28s-a%29%28s-b%29%28s-c%29

where





so, substituting to eliminate s,

A%5E2=s%28s-a%29%28s-b%29%28s-c%29



A%5E2=%28%28a%2Bb%2Bc%29%28-a%2Bb%2Bc%29%28a-b%2Bc%29%28a%2Bb-c%29%29%2F16

16A%5E2=%28a%2Bb%2Bc%29%28-a%2Bb%2Bc%29%28a-b%2Bc%29%28a%2Bb-c%29

Now that we have rewritten Heron's formula in terms of the
sides only, we simplify the factors to substitute in
the above revised version of Heron's formula, which I think
is superior to the original version, especially for 
calculating purposes.

So now we substitute a=2, b=5, c=x, and A=x

A%5E2=%285%29%5E2=25
a%2Bb%2Bc+=+2%2B5%2Bx=7%2Bx
-a%2Bb%2Bc+=+-2%2B5%2Bx=3%2Bx
a-b%2Bc+=+2-5%2Bx=-3%2Bx
a%2Bb-c+=+2%2B5-x=7-x

Substituting these factors:

16A%5E2=%28a%2Bb%2Bc%29%28a%2Bb-c%29%28a-b%2Bc%29%28-a%2Bb%2Bc%29%29

16%2825%29=%287%2Bx%29%283%2Bx%29%28-3%2Bx%29%287-x%29

400=%287%2Bx%29%287-x%29%283%2Bx%29%28-3%2Bx%29

400=%2849-x%5E2%29%28-9%2Bx%5E2%29

400=-441%2B58x-x%5E4

841=58x-x%5E4%29

x%5E4-58x%2B841=0

That factors as

%28x-29%29%28x-29%29=0

So x-29=0

and x=29

Edwin