SOLUTION: The sum of the measures of the interior angles of a triangle are 180 deg. If the measure of one angle is twice the measure of a second angle, and the measure of a third angle is 40
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Question 257991: The sum of the measures of the interior angles of a triangle are 180 deg. If the measure of one angle is twice the measure of a second angle, and the measure of a third angle is 40 deg less than the second, find the measure of all three angles of the triangle. Answer by Greenfinch(383) (Show Source):
You can put this solution on YOUR website! Let first angle be 2y, then second angle is y and the third is y - 40.
Sum is y + 2y + y - 40 = 180
4y = 220
y = 55
So angles are 110, 55, 15