SOLUTION: i don't remember how to do this: (2^-3*x^-4*y^-3)/ (x^3*y^-2)^-1 i am supposed to write this with only positive exponents

Algebra ->  Exponents -> SOLUTION: i don't remember how to do this: (2^-3*x^-4*y^-3)/ (x^3*y^-2)^-1 i am supposed to write this with only positive exponents      Log On


   

Question 257955: i don't remember how to do this:
(2^-3*x^-4*y^-3)/ (x^3*y^-2)^-1
i am supposed to write this with only positive exponents
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
A negative exponent means use the reciprocal.
In the case of x/y it becomes y/x
In the case of z It becomes 1/z
and in the case of 1/w it becomes w
Let's start with the numerator where every term has a negative exponent.
+%282%5E-3%2Ax%5E-4%2Ay%5E-3%29%2F%28x%5E3%2Ay%5E-2%29%5E-1
1%2F%282%5E3%2Ax%5E4%2Ay%5E3%29
But we also notice that the entire denominator has a negative exponent.
So the fraction becomes:
%28x%5E3%2Ay%5E-2%29%2F%282%5E3%2Ax%5E4%2Ay%5E3%29
But the y term in the numerator has a negative exponent.
%28x%5E3%2F%282%5E3%2Ax%5E4%2Ay%5E3%2Ay%5E2%29%29
We have dealt with all the negative exponents. Now to reduce and combine
2^3=8
x^3/x^4=1/x
y^2*y^3=y^5
1%2F%288xy%5E5%29%29