SOLUTION: find the rational roots of 4x^3-3x-1=0. please & thanks.

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Question 257946: find the rational roots of 4x^3-3x-1=0.
please & thanks.
Answer by Greenfinch(383) About Me  (Show Source):
You can put this solution on YOUR website!
Find first root using remainder theorem
Try x = 1 f(1) = 0
So (x - 1) is a factor
so x - 1 divided into 4x^3 - 3x -1 is 4x^2 -4x +1 = 4(x^2 -x + 1/4) = 4(x - 1/2)^2
So roots are x = 1 and 1/2 (twice)