SOLUTION: A mixture of acid and water is 35% acid. if the mixture contains a total of 40 Liters, how many liters of pure acid are in the mixture? How many liters of pure water are in the mix

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Question 257812: A mixture of acid and water is 35% acid. if the mixture contains a total of 40 Liters, how many liters of pure acid are in the mixture? How many liters of pure water are in the mixture?
Found 2 solutions by drk, amalm06:
Answer by drk(1908) About Me  (Show Source):
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This is a mixture problem. Be careful here, as pure acid = 100% acid and water = 0% acid. As a matter of fact any time they give you water it is automatically 0 in the % column. WE have the following table based on given information:
liquid . . . . . . . . . .% . . . . . . . . . . .L . . . . . . . . .%xL
acid . . . . . .. . . . . 100 . . . . . . . . . x . . . . . . . . .100x
water . . . . .. . . . . 0 . . . . . . . . . .. 40-x . . . .. . . . 0
mix . . . . .. . . . . . 35 . . . . . . . . . .40 . . . . . .. .. . 1400
From the third column, we get
100x = 1400
x = 14.
So we have
14 Liters of pure acid
26 liters of pure water

Answer by amalm06(224) About Me  (Show Source):
You can put this solution on YOUR website!
35% of 40 = 14 liters pure acid (Answer)

40-14=26 liters water (Answer)