SOLUTION: The tens digit of a two digit number is 3 more than the units digit. The number is 8 more than six times the sum of the digits. Find the number?

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Question 257750: The tens digit of a two digit number is 3 more than the units digit. The number is 8 more than six times the sum of the digits. Find the number?
Found 2 solutions by checkley77, dabanfield:
Answer by checkley77(12844) (Show Source):
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X=Y+3
10X+Y=6(X+Y)+8
10(Y+3)+Y=6(Y+3+Y)+8
10Y+30+Y=6(2Y+3)+8
10Y+30=12Y+18+8
10Y-12Y=18+8-30
-Y=26-30
-Y=-4
Y=4 ANS. FOR THE UNITS DIGIT.
X=4+3=7 ANS. FOR THE TENS DIGIT.
PROOF:
10*7+4=6(7+4)+8
70+4=6*11+8
74=66+8
74=74

Answer by dabanfield(803) (Show Source):
You can put this solution on YOUR website!
The tens digit of a two digit number is 3 more than the units digit. The number is 8 more than six times the sum of the digits. Find the number?
Let x be the tens digit and y the ones digit. Then the numbr itself is equal to 10*x + y.
We have then:
1.) x = y + 3 and
2.) 10*x + y = 6*(x+y) + 8
Substitute y + 3 from 1.) for x in 2.) and solve 2.) for y. Once you have the value of y, calculate x = y + 3 (from 1.)