Question 25772: A baseball coach is determining the batting order for the team. The team has 9 members, but the coach doesnt want the pitcher to be one of the first four to bat. How many batting orders are possible?
Answer by venugopalramana(3286)   (Show Source):
You can put this solution on YOUR website! USE THE BOX METHOD
HAVE 9 BOXES FOR 9 POSITIONS TO BAT
THERE ARE 9 PEOPLE TO GO INCLUDING THE PITCHER
WE CAN SELECT ONE OUT 9-1=8 FOR 1 ST. POSITION AS PITCHER CANNOT GO IN FIRST FOUR , IN ...........................8 WAYS
WE CAN SELECT ONE OUT 8-1=7 FOR 2 ND.. POSITION AS PITCHER CANNOT GO IN FIRST FOUR , IN ...........................7 WAYS
WE CAN SELECT ONE OUT 7-1=6 FOR 3 RD. POSITION AS PITCHER CANNOT GO IN FIRST FOUR , IN ...........................6 WAYS
WE CAN SELECT ONE OUT 6-1=5 FOR 4 TH. POSITION AS PITCHER CANNOT GO IN FIRST FOUR , IN ...........................5 WAYS
WE CAN SELECT ONE OUT 5 FOR 5 TH. POSITION IN ..........5 WAYS
WE CAN SELECT ONE OUT 4 FOR 6 TH. POSITION IN ..........4 WAYS
WE CAN SELECT ONE OUT 3 FOR 7 TH. POSITION IN ..........3 WAYS
WE CAN SELECT ONE OUT 2 FOR 8 TH. POSITION IN ..........2 WAYS
WE CAN SELECT ONE OUT 1 FOR 9 TH. POSITION IN ..........1 WAY
HENCE NUMBER OF POSSIBILITIES =8*7*6*5*5*4*3*2*1=
|
|
|
