SOLUTION: if 3 persons selected at random, are stopped on a street, what are the probabilities that
1. all were born on monday.
2. two were born on a monday and other on tuesday
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-> SOLUTION: if 3 persons selected at random, are stopped on a street, what are the probabilities that
1. all were born on monday.
2. two were born on a monday and other on tuesday
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Question 257627: if 3 persons selected at random, are stopped on a street, what are the probabilities that
1. all were born on monday.
2. two were born on a monday and other on tuesday Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! if 3 persons selected at random, are stopped on a street, what are the probabilities that
1. all were born on monday.
Ans: (1/7)^3 = 1/343
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2. two were born on a monday and other on tuesday
P(2monday and one tuesday) = P(2monday)*P(onetuesday)
= [3C2(1/7)^2*(1/7)]
= 3(1/7)^3 * 3(1/7)^3
= 9/343
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Cheers,
Stan H.
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