SOLUTION: An object's altitude, in meters, is given by the polynomial h + vt - 9.8t2, where h is the height in meters from which the launch occurs, v is the initial upward speed in meters pe

Algebra ->  Inequalities -> SOLUTION: An object's altitude, in meters, is given by the polynomial h + vt - 9.8t2, where h is the height in meters from which the launch occurs, v is the initial upward speed in meters pe      Log On


   

Question 257589: An object's altitude, in meters, is given by the polynomial h + vt - 9.8t2, where h is the height in meters from which the launch occurs, v is the initial upward speed in meters per second, and t is the number of seconds for which the object is airborne. A pebble is shot upward from the top of a building 164 meters tall. If the initial speed is 36 meters per second, how high above the ground will the pebble be after 3 seconds? Round results to the nearest tenth of a meter
Answer by stanbon(75887) About Me  (Show Source):
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An object's altitude, in meters, is given by the polynomial h + vt - 9.8t2, where h is the height in meters from which the launch occurs, v is the initial upward speed in meters per second, and t is the number of seconds for which the object is airborne.
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A pebble is shot upward from the top of a building 164 meters tall. If the initial speed is 36 meters per second, how high above the ground will the pebble be after 3 seconds? Round results to the nearest tenth of a meter
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a(t) = h + vt - 9.8t^2
a(3) = 164 + 36(3) - 9(3)^2
a(3) = 164 + 108 - 81
a(3) = 191 meters
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Cheers,
Stan H.
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