SOLUTION: I've done pretty good with ratios and proportions until I hit this one and I'm stumped. The question reads: A baseball players batting average is the ratio of number of hits to n

Algebra ->  Polygons -> SOLUTION: I've done pretty good with ratios and proportions until I hit this one and I'm stumped. The question reads: A baseball players batting average is the ratio of number of hits to n      Log On


   

Question 257571: I've done pretty good with ratios and proportions until I hit this one and I'm stumped. The question reads: A baseball players batting average is the ratio of number of hits to number of times at bat. A player has 10 hits out of 20 times at bat. How many consecutive times at bat must a hit be made to raise his average to .600?
I'm guessing that somehow I have to use his current average of .500 but I can't figure out how to set up the equation to get the .600.
Thanks for any help,
Laura
Found 3 solutions by scott8148, rfer, dabanfield:
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
(10 + x) / (20 + x) = .6

10 + x = 12 + .6x

.4x = 2

x = 5

Answer by rfer(16322) About Me  (Show Source):
Answer by dabanfield(803) About Me  (Show Source):
You can put this solution on YOUR website!
A baseball players batting average is the ratio of number of hits to number of times at bat. A player has 10 hits out of 20 times at bat. How many consecutive times at bat must a hit be made to raise his average to .600?
Batting Average = number of hits / number of times at bat.
Right now the batter's average is 10/20.
Let x be the number of consecutive hits needed to raise the average to .600.
Then after x more hits (and also x at bats) the batting average is (10+x)/(20+x)
So we must have:
(10+x)/(20+x) = .600
Solve the above for x:
10+x = .600*(20+x)
10+x = 12 + .6x
.4x = 2
x = 5