SOLUTION: How do I divide the polynomial(-9ab^2-6a^3b^3) by a monomial(-3ab^2)?

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: How do I divide the polynomial(-9ab^2-6a^3b^3) by a monomial(-3ab^2)?      Log On


   

Question 257567: How do I divide the polynomial(-9ab^2-6a^3b^3) by a monomial(-3ab^2)?
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
(-9ab^2-6a^3b^3)/(-3ab^2)
%28-9ab%5E2-6a%5E3b%5E3%29%2F%28-3ab%5E2%29
Can you see that -3ab is a factor of -9ab and also of -6ab?
but we can also factor out b^2
%28-3ab%5E2%29%283%2B2a%5E2b%29%2F%28-3ab%5E2%29=3+2a^2b