Question 257542: (This question involves Binomial Distribution..)An urn contains 10 red balls and 5 blue balls. Five balls are chosen at random with replacement from this urn.
(a) What is the probability that all five balls drawn are red?
(b) What is the probability that among those five there are at least one red ball and also at least one blue ball?
(C) (This involves permutations.)Suppose that the 10 red balls are labeled as R1, R2, ..., R10 and they are randomly arranged in a single line. What is the probability that R1, R2 and R3 are in adjacent positions?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! (This involves permutations.)Suppose that the 10 red balls are labeled as R1, R2, ..., R10 and they are randomly arranged in a single line. What is the probability that R1, R2 and R3 are in adjacent positions?
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Since the 3 must place together
there are only 8! arranements.
But the 3 can be arranged among themselves in 3! = 6 ways.
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Total arrangements 8!*6 = 241920 arrangements.
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Cheers,
Stan H.
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