SOLUTION: This problem is an example in my book:
2(3x^2-2x+5) + (x^2+3x-7)distribute, remove parentheses
= 2(3x^2-2x+5) + 1(x^2+3x-7)
Can you please explain where the 1 comes from?
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: This problem is an example in my book:
2(3x^2-2x+5) + (x^2+3x-7)distribute, remove parentheses
= 2(3x^2-2x+5) + 1(x^2+3x-7)
Can you please explain where the 1 comes from?
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Question 257538: This problem is an example in my book:
2(3x^2-2x+5) + (x^2+3x-7)distribute, remove parentheses
= 2(3x^2-2x+5) + 1(x^2+3x-7)
Can you please explain where the 1 comes from? Answer by rfer(16322) (Show Source):
You can put this solution on YOUR website! In this case the 1 changes nothing, just ignor it. If it was a -1 then things would change.
2(3x^2-2x+5)+(x^2+3x-7)=2(3x^2-2x+5)+1(x^2+3x-7)
6x^2-4x+10+x^2+3x-7=6x^2-4x+10+x^2+3x-7
7x^2-x+3=7x^2-x+3
everything cancils
=0
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