Question 257452: For the scores 60, 49, 58, 45, 55, 62, 49 find the following:
a.) mean - 54
b.) median - 55
c.) mode - 49
d.) range- 9
e.) interquartile range- 11
f.) standard deviation-
(that i am stuck on) I hope I did the rest correct. Could you please explain how to get that standard deviation?
Answer by Edwin McCravy(20056)   (Show Source):
You can put this solution on YOUR website!
List them in a column, like this
60
49
58
45
55
62
49
Subtract the mean, 54, from each one in the next column, like this
60 60 - 54 = 6
49 49 - 54 = -5
58 58 - 54 = 4
45 45 - 54 = -9
55 55 - 54 = 1
62 62 - 54 = 8
49 49 - 54 = -5
Square these results in the next column
60 60 - 54 = 6 (6)2 = 36
49 49 - 54 = -5 (-5)2 = 25
58 58 - 54 = 4 (4)2 = 16
45 45 - 54 = -9 (-9)2 = 81
55 55 - 54 = 1 (1)2 = 1
62 62 - 54 = 8 (8)2 = 64
49 49 - 54 = -5 (-5)2 = 25
Add those squares up, like this
60 60 - 54 = 6 (6)2 = 36
49 49 - 54 = -5 (-5)2 = 25
58 58 - 54 = 4 (4)2 = 16
45 45 - 54 = -10 (-9)2 = 81
55 55 - 54 = 1 (1)2 = 1
62 62 - 54 = 8 (8)2 = 64
49 49 - 54 = -5 (-5)2 = 25
-----
248
There are 7 numbers. Subtract 1, getting 6
Divide 248 by 6, getting 41.33333333
Take the square root of 41.33333333, getting 6.429100507
That's the standard deviation
Edwin
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