SOLUTION: If n = 3^x + 3^x + 3^x , then n^2 = A^(x+1). Determine the value of A.
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Question 257434
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If n = 3^x + 3^x + 3^x , then n^2 = A^(x+1). Determine the value of A.
Answer by
richwmiller(17219)
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n = 3^x + 3^x + 3^x and n^2 = A^(x+1)
n = 3^(x+1)and n^2 = A^(x+1)
n^2=(3^(x+1))^2
A^(x+1)=(3^(x+1))^2
A^(x+1)=9^(x+1)
A=9