SOLUTION: the cost of labor for producing x transmissions is L(x) = 0.3x^2 + 400x + 550 dollars, while the cost of materials is M(x) = 0.1x^2 + 50x + 800 dollars. write a polynomial T(x) tha
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-> SOLUTION: the cost of labor for producing x transmissions is L(x) = 0.3x^2 + 400x + 550 dollars, while the cost of materials is M(x) = 0.1x^2 + 50x + 800 dollars. write a polynomial T(x) tha
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Question 257333: the cost of labor for producing x transmissions is L(x) = 0.3x^2 + 400x + 550 dollars, while the cost of materials is M(x) = 0.1x^2 + 50x + 800 dollars. write a polynomial T(x) that represents the total cost of materials and labor for producing x transmissions. Answer by drk(1908) (Show Source):
You can put this solution on YOUR website! Total cost of labor and materials is addition.
So, L(x) + M(x) = T(x). We can express that as
combining like terms gets us
(