SOLUTION: find 3 consecutive odd numbers where the product of the smaller two numbers is 34 less than the square of the largest number.?

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Question 257261: find 3 consecutive odd numbers where the product of the smaller two numbers is 34 less than the square of the largest number.?
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
Let x, x+2, and x+4 be the 3 consecutive odd integers.
From above, we have:
(i) %28x%29%28x%2B2%29+=+%28x%2B4%29%5E2+-+34
by foiling, we get
(ii) x%5E2+%2B+2x+=+x%5E2++%2B+8x+%2B+16+-+34
simplifying we get
(iii) x%5E2+%2B+2x+=+x%5E2+%2B+8x+-+18
setting = 0, we get
(iv) 6x+-+18+=+0
solving for x, we get
x+=+3
If x = 3, the 3 consecutive odd integers are {3, 5, 7}