SOLUTION: the sides of paralelograms are x+y+1, x+2, 3x-4, 2y-x. find x and y and also find the perimeter of paralellogram.

Algebra ->  Linear-equations -> SOLUTION: the sides of paralelograms are x+y+1, x+2, 3x-4, 2y-x. find x and y and also find the perimeter of paralellogram.      Log On


   

Question 257249: the sides of paralelograms are x+y+1, x+2, 3x-4, 2y-x. find x and y and also find the perimeter of paralellogram.
Found 2 solutions by richwmiller, CharlesG2:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
x+2=3x-4
x+y+1= 2y-x
x=3 y=7
plug in 3 for x and 7 for y and up the the four sides to get the perimeter

Answer by CharlesG2(834) About Me  (Show Source):
You can put this solution on YOUR website!
the sides of paralelograms are x+y+1, x+2, 3x-4, 2y-x. find x and y and also find the perimeter of paralellogram.
a parallelogram is essentially just a rectangle that has been skewed (top of rectangle moved to left or to the right ) by some angle
(oops accidentally posted at this point without solving problem, sorry for any inconvenience that this may of caused)
(let me solve problem now)
P perimeter = (x+y+1) + (x+2) + (3x-4) + (2y-x)
first system of equations:
(x+y+1)=(3x-4)
(x+2)=(2y-x)
solving:
(x+y+1)=(3x-4)
x+y+1=3x-4
y+1=2x-4
y=2x-3
(x+y)=(2y-x) plugging in y=2x-3
x+2x-3=2(2x-3)-x
x+2x-3=4x-6-x
3x-3=3x-6
well this does not work, need to try new system of equations
2nd system of equations
(x+y+1)=(x+2)
(3x-4)=(2y-x)
solving:
(x+y+1)=(x+2)
x+y+1=x+2
y+1=2
y=1
(3x-4)=(2y-x) plugging in y=1
3x-4=2(1)-x
3x-4=2-x
4x-4=2
4x=6
x=6/4
x=3/2
x=3/2 and y=1
P perimeter = (x+y+1) + (x+2) + (3x-4) + (2y-x)
P=(3/2+1+1)+(3/2+1+1)+(3*3/2 - 4)+(2*1-3/2)
P=(3/2+2)+(3/2+2)+(9/2-4)+(2-3/2)
P=(3/2+4/2)+(3/2+4/2)+(9/2-8/2)+(4/2-3/2)
P=7/2+7/2+1/2+1/2
P=14/2+1
P=7+2
P=8