Question 257226: Could someone please help me with this word problem?
Thank you!
A fish swims 12 miles down stream in 2 hours, the fish swims back up stream to the same point but the trip takes 3 hours. Assume the speed of the current was constant and the fish swims along the same path.
Write a system of linear equation to describe the situation. Determine the speed of the fish in still water and determine the speed of the current?
Answer by drk(1908)   (Show Source):
You can put this solution on YOUR website! This is an RTD question. Here is a table based on the given information.
water . . . . . . . .rate . . . . . .time . . . . . . . . .distance
up . . . . . . . . . .r -c = 4 . . . .3 . . . . . . . . . . . .12
down . . . . . . . r+c = 6 . . . . 2 . . . . . . . . . . . .12
since, uptream distance = 12, and time = 2, rate = 6
since downstream distance = 12, and time = 3, rate = 4
We have two equations as
(i) r-c = 4
(ii) r+c = 6
adding together, we get
(iii) 2r = 10
r = 5
5 mph in still water
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