SOLUTION: chris drove to a friends house at a rate of 40 mi/h. he returned by the same route at a rate of 45 mi/h, the driving time fro the round trip was 4 h, whats the total distance chris
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Question 257225: chris drove to a friends house at a rate of 40 mi/h. he returned by the same route at a rate of 45 mi/h, the driving time fro the round trip was 4 h, whats the total distance chris travled? Answer by drk(1908) (Show Source):
You can put this solution on YOUR website! This is an RTD problem. Here is the table based on the given information:
speeds . . . . . . . . . rate . . . . . . . . . . . .time . . . . . . . . . . . .distance
A . . . . . . . . . . . . . . 40 . . . . . . . . . . . . x . . . . . . . .. . . . . . .. . 40x
B . . . . . . . . . . . . . . 45 . . . . . . . . . . . . 4-x . . . . . . . . . . . . . . 180 - 45x
average . . . . . . . . . . . . .. . . . . . . . . . .. 4 . . . . . . . .. . . . . .. . . . .
The distances must be equal, so
The distance is: ~ 84.71 miles
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