SOLUTION: determine the solution of the equation 7-6x-x^2=0

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Question 257202: determine the solution of the equation 7-6x-x^2=0
Answer by Theo(13342) (Show Source):
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7-6x-x^2=0

reorder the terms so you get:

-x^2 - 6x + 7 = 0

multiply both sides of the equation by -1 to get:

x^2 + 6x - 7 = 0

factor to get:

(x+7) * (x-1) = 0

you get:

x = -7 or x = 1

plug into your original equation to see if these values are good.

your original equation is:

7-6x-x^2=0

when x = -7 this becomes 7 - 6*(-7) - (-7)^2 = 7 + 42 - 49 = 49 - 49 = 0.

when x = 1, this becomes 7 - 6*1 - 1^2 = 7 - 6 - 1 = 7 - 7 = 0.

both values of x are good.

your answer is:

the solution to the equation of 7 - 6x - x^2 = 0 is x = -7 or x = 1. both solutions are valid.